7=x(x^2+3x-41)

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Solution for 7=x(x^2+3x-41) equation: 



7=x(x^2+3x-41)

We move all terms to the left:

7-(x(x^2+3x-41))=0



We calculate terms in parentheses: -(x(x^2+3x-41)), so:

x(x^2+3x-41)

We multiply parentheses

x^3+3x^2-41x

We do not support expression: x^3

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